3.127 \(\int \frac{x^m \left (A+B x^3\right )}{a+b x^3} \, dx\)

Optimal. Leaf size=66 \[ \frac{x^{m+1} (A b-a B) \, _2F_1\left (1,\frac{m+1}{3};\frac{m+4}{3};-\frac{b x^3}{a}\right )}{a b (m+1)}+\frac{B x^{m+1}}{b (m+1)} \]

[Out]

(B*x^(1 + m))/(b*(1 + m)) + ((A*b - a*B)*x^(1 + m)*Hypergeometric2F1[1, (1 + m)/
3, (4 + m)/3, -((b*x^3)/a)])/(a*b*(1 + m))

_______________________________________________________________________________________

Rubi [A]  time = 0.108708, antiderivative size = 66, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.1 \[ \frac{x^{m+1} (A b-a B) \, _2F_1\left (1,\frac{m+1}{3};\frac{m+4}{3};-\frac{b x^3}{a}\right )}{a b (m+1)}+\frac{B x^{m+1}}{b (m+1)} \]

Antiderivative was successfully verified.

[In]  Int[(x^m*(A + B*x^3))/(a + b*x^3),x]

[Out]

(B*x^(1 + m))/(b*(1 + m)) + ((A*b - a*B)*x^(1 + m)*Hypergeometric2F1[1, (1 + m)/
3, (4 + m)/3, -((b*x^3)/a)])/(a*b*(1 + m))

_______________________________________________________________________________________

Rubi in Sympy [A]  time = 10.4017, size = 49, normalized size = 0.74 \[ \frac{B x^{m + 1}}{b \left (m + 1\right )} + \frac{x^{m + 1} \left (A b - B a\right ){{}_{2}F_{1}\left (\begin{matrix} 1, \frac{m}{3} + \frac{1}{3} \\ \frac{m}{3} + \frac{4}{3} \end{matrix}\middle |{- \frac{b x^{3}}{a}} \right )}}{a b \left (m + 1\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate(x**m*(B*x**3+A)/(b*x**3+a),x)

[Out]

B*x**(m + 1)/(b*(m + 1)) + x**(m + 1)*(A*b - B*a)*hyper((1, m/3 + 1/3), (m/3 + 4
/3,), -b*x**3/a)/(a*b*(m + 1))

_______________________________________________________________________________________

Mathematica [A]  time = 0.0907811, size = 55, normalized size = 0.83 \[ \frac{x^{m+1} \left ((A b-a B) \, _2F_1\left (1,\frac{m+1}{3};\frac{m+4}{3};-\frac{b x^3}{a}\right )+a B\right )}{a b (m+1)} \]

Antiderivative was successfully verified.

[In]  Integrate[(x^m*(A + B*x^3))/(a + b*x^3),x]

[Out]

(x^(1 + m)*(a*B + (A*b - a*B)*Hypergeometric2F1[1, (1 + m)/3, (4 + m)/3, -((b*x^
3)/a)]))/(a*b*(1 + m))

_______________________________________________________________________________________

Maple [F]  time = 0.053, size = 0, normalized size = 0. \[ \int{\frac{{x}^{m} \left ( B{x}^{3}+A \right ) }{b{x}^{3}+a}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int(x^m*(B*x^3+A)/(b*x^3+a),x)

[Out]

int(x^m*(B*x^3+A)/(b*x^3+a),x)

_______________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (B x^{3} + A\right )} x^{m}}{b x^{3} + a}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x^3 + A)*x^m/(b*x^3 + a),x, algorithm="maxima")

[Out]

integrate((B*x^3 + A)*x^m/(b*x^3 + a), x)

_______________________________________________________________________________________

Fricas [F]  time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{{\left (B x^{3} + A\right )} x^{m}}{b x^{3} + a}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x^3 + A)*x^m/(b*x^3 + a),x, algorithm="fricas")

[Out]

integral((B*x^3 + A)*x^m/(b*x^3 + a), x)

_______________________________________________________________________________________

Sympy [A]  time = 93.2513, size = 190, normalized size = 2.88 \[ \frac{A m x x^{m} \Phi \left (\frac{b x^{3} e^{i \pi }}{a}, 1, \frac{m}{3} + \frac{1}{3}\right ) \Gamma \left (\frac{m}{3} + \frac{1}{3}\right )}{9 a \Gamma \left (\frac{m}{3} + \frac{4}{3}\right )} + \frac{A x x^{m} \Phi \left (\frac{b x^{3} e^{i \pi }}{a}, 1, \frac{m}{3} + \frac{1}{3}\right ) \Gamma \left (\frac{m}{3} + \frac{1}{3}\right )}{9 a \Gamma \left (\frac{m}{3} + \frac{4}{3}\right )} + \frac{B m x^{4} x^{m} \Phi \left (\frac{b x^{3} e^{i \pi }}{a}, 1, \frac{m}{3} + \frac{4}{3}\right ) \Gamma \left (\frac{m}{3} + \frac{4}{3}\right )}{9 a \Gamma \left (\frac{m}{3} + \frac{7}{3}\right )} + \frac{4 B x^{4} x^{m} \Phi \left (\frac{b x^{3} e^{i \pi }}{a}, 1, \frac{m}{3} + \frac{4}{3}\right ) \Gamma \left (\frac{m}{3} + \frac{4}{3}\right )}{9 a \Gamma \left (\frac{m}{3} + \frac{7}{3}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x**m*(B*x**3+A)/(b*x**3+a),x)

[Out]

A*m*x*x**m*lerchphi(b*x**3*exp_polar(I*pi)/a, 1, m/3 + 1/3)*gamma(m/3 + 1/3)/(9*
a*gamma(m/3 + 4/3)) + A*x*x**m*lerchphi(b*x**3*exp_polar(I*pi)/a, 1, m/3 + 1/3)*
gamma(m/3 + 1/3)/(9*a*gamma(m/3 + 4/3)) + B*m*x**4*x**m*lerchphi(b*x**3*exp_pola
r(I*pi)/a, 1, m/3 + 4/3)*gamma(m/3 + 4/3)/(9*a*gamma(m/3 + 7/3)) + 4*B*x**4*x**m
*lerchphi(b*x**3*exp_polar(I*pi)/a, 1, m/3 + 4/3)*gamma(m/3 + 4/3)/(9*a*gamma(m/
3 + 7/3))

_______________________________________________________________________________________

GIAC/XCAS [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (B x^{3} + A\right )} x^{m}}{b x^{3} + a}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x^3 + A)*x^m/(b*x^3 + a),x, algorithm="giac")

[Out]

integrate((B*x^3 + A)*x^m/(b*x^3 + a), x)